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package org.locationtech.jts.index.strtree; |
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|
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import java.io.Serializable; |
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import java.util.ArrayList; |
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import java.util.Collections; |
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import java.util.Comparator; |
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import java.util.Iterator; |
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import java.util.List; |
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import java.util.PriorityQueue; |
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|
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import org.locationtech.jts.geom.Envelope; |
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import org.locationtech.jts.index.ItemVisitor; |
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import org.locationtech.jts.index.SpatialIndex; |
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import org.locationtech.jts.util.Assert; |
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|
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|
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/** |
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* A query-only R-tree created using the Sort-Tile-Recursive (STR) algorithm. |
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* For two-dimensional spatial data. |
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* <P> |
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* The STR packed R-tree is simple to implement and maximizes space |
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* utilization; that is, as many leaves as possible are filled to capacity. |
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* Overlap between nodes is far less than in a basic R-tree. However, once the |
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* tree has been built (explicitly or on the first call to #query), items may |
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* not be added or removed. |
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* <P> |
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* Described in: P. Rigaux, Michel Scholl and Agnes Voisard. |
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* <i>Spatial Databases With Application To GIS</i>. |
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* Morgan Kaufmann, San Francisco, 2002. |
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* <p> |
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* <b>Note that inserting items into a tree is not thread-safe.</b> |
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* Inserting performed on more than one thread must be synchronized externally. |
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* <p> |
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* Querying a tree is thread-safe. |
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* The building phase is done synchronously, |
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* and querying is stateless. |
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* |
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* @version 1.7 |
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*/ |
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public class STRtree extends AbstractSTRtree |
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implements SpatialIndex, Serializable |
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{ |
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|
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private static final class STRtreeNode extends AbstractNode |
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{ |
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private STRtreeNode(int level) |
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{ |
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super(level); |
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} |
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|
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protected Object computeBounds() { |
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Envelope bounds = null; |
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for (Iterator i = getChildBoundables().iterator(); i.hasNext(); ) { |
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Boundable childBoundable = (Boundable) i.next(); |
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if (bounds == null) { |
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bounds = new Envelope((Envelope)childBoundable.getBounds()); |
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} |
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else { |
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bounds.expandToInclude((Envelope)childBoundable.getBounds()); |
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} |
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} |
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return bounds; |
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} |
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} |
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|
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/** |
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* |
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*/ |
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private static final long serialVersionUID = 259274702368956900L; |
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|
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private static Comparator xComparator = |
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new Comparator() { |
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public int compare(Object o1, Object o2) { |
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return compareDoubles( |
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centreX((Envelope)((Boundable)o1).getBounds()), |
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centreX((Envelope)((Boundable)o2).getBounds())); |
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} |
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}; |
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private static Comparator yComparator = |
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new Comparator() { |
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public int compare(Object o1, Object o2) { |
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return compareDoubles( |
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centreY((Envelope)((Boundable)o1).getBounds()), |
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centreY((Envelope)((Boundable)o2).getBounds())); |
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} |
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}; |
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|
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private static double centreX(Envelope e) { |
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return avg(e.getMinX(), e.getMaxX()); |
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} |
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|
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private static double centreY(Envelope e) { |
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return avg(e.getMinY(), e.getMaxY()); |
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} |
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|
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private static double avg(double a, double b) { return (a + b) / 2d; } |
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|
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private static IntersectsOp intersectsOp = new IntersectsOp() { |
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public boolean intersects(Object aBounds, Object bBounds) { |
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return ((Envelope)aBounds).intersects((Envelope)bBounds); |
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} |
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}; |
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|
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/** |
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* Creates the parent level for the given child level. First, orders the items |
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* by the x-values of the midpoints, and groups them into vertical slices. |
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* For each slice, orders the items by the y-values of the midpoints, and |
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* group them into runs of size M (the node capacity). For each run, creates |
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* a new (parent) node. |
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*/ |
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protected List createParentBoundables(List childBoundables, int newLevel) { |
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Assert.isTrue(!childBoundables.isEmpty()); |
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int minLeafCount = (int) Math.ceil((childBoundables.size() / (double) getNodeCapacity())); |
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ArrayList sortedChildBoundables = new ArrayList(childBoundables); |
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Collections.sort(sortedChildBoundables, xComparator); |
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List[] verticalSlices = verticalSlices(sortedChildBoundables, |
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(int) Math.ceil(Math.sqrt(minLeafCount))); |
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return createParentBoundablesFromVerticalSlices(verticalSlices, newLevel); |
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} |
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|
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private List createParentBoundablesFromVerticalSlices(List[] verticalSlices, int newLevel) { |
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Assert.isTrue(verticalSlices.length > 0); |
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List parentBoundables = new ArrayList(); |
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for (int i = 0; i < verticalSlices.length; i++) { |
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parentBoundables.addAll( |
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createParentBoundablesFromVerticalSlice(verticalSlices[i], newLevel)); |
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} |
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return parentBoundables; |
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} |
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|
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protected List createParentBoundablesFromVerticalSlice(List childBoundables, int newLevel) { |
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return super.createParentBoundables(childBoundables, newLevel); |
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} |
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|
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/** |
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* @param childBoundables Must be sorted by the x-value of the envelope midpoints |
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*/ |
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protected List[] verticalSlices(List childBoundables, int sliceCount) { |
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int sliceCapacity = (int) Math.ceil(childBoundables.size() / (double) sliceCount); |
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List[] slices = new List[sliceCount]; |
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Iterator i = childBoundables.iterator(); |
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for (int j = 0; j < sliceCount; j++) { |
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slices[j] = new ArrayList(); |
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int boundablesAddedToSlice = 0; |
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while (i.hasNext() && boundablesAddedToSlice < sliceCapacity) { |
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Boundable childBoundable = (Boundable) i.next(); |
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slices[j].add(childBoundable); |
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boundablesAddedToSlice++; |
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} |
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} |
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return slices; |
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} |
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|
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private static final int DEFAULT_NODE_CAPACITY = 10; |
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|
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/** |
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* Constructs an STRtree with the default node capacity. |
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*/ |
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public STRtree() |
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{ |
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this(DEFAULT_NODE_CAPACITY); |
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} |
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|
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/** |
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* Constructs an STRtree with the given maximum number of child nodes that |
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* a node may have. |
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* <p> |
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* The minimum recommended capacity setting is 4. |
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* |
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*/ |
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public STRtree(int nodeCapacity) { |
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super(nodeCapacity); |
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} |
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|
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protected AbstractNode createNode(int level) { |
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return new STRtreeNode(level); |
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} |
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|
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protected IntersectsOp getIntersectsOp() { |
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return intersectsOp; |
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} |
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|
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/** |
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* Inserts an item having the given bounds into the tree. |
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*/ |
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public void insert(Envelope itemEnv, Object item) { |
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if (itemEnv.isNull()) { return; } |
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super.insert(itemEnv, item); |
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} |
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|
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/** |
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* Returns items whose bounds intersect the given envelope. |
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*/ |
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public List query(Envelope searchEnv) { |
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|
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return super.query(searchEnv); |
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} |
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|
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/** |
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* Returns items whose bounds intersect the given envelope. |
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*/ |
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public void query(Envelope searchEnv, ItemVisitor visitor) { |
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|
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|
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super.query(searchEnv, visitor); |
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} |
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|
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/** |
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* Removes a single item from the tree. |
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* |
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* @param itemEnv the Envelope of the item to remove |
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* @param item the item to remove |
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* @return <code>true</code> if the item was found |
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*/ |
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public boolean remove(Envelope itemEnv, Object item) { |
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return super.remove(itemEnv, item); |
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} |
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|
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/** |
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* Returns the number of items in the tree. |
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* |
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* @return the number of items in the tree |
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*/ |
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public int size() |
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{ |
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return super.size(); |
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} |
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|
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/** |
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* Returns the number of items in the tree. |
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* |
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* @return the number of items in the tree |
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*/ |
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public int depth() |
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{ |
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return super.depth(); |
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} |
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|
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protected Comparator getComparator() { |
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return yComparator; |
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} |
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|
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/** |
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* Finds the two nearest items in the tree, |
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* using {@link ItemDistance} as the distance metric. |
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* A Branch-and-Bound tree traversal algorithm is used |
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* to provide an efficient search. |
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* <p> |
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* If the tree is empty, the return value is <code>null</code. |
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* If the tree contains only one item, |
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* the return value is a pair containing that item. |
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* <b> |
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* If it is required to find only pairs of distinct items, |
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* the {@link ItemDistance} function must be <b>anti-reflexive</b>. |
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* |
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* @param itemDist a distance metric applicable to the items in this tree |
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* @return the pair of the nearest items |
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* or <code>null</code> if the tree is empty |
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*/ |
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public Object[] nearestNeighbour(ItemDistance itemDist) |
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{ |
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if (isEmpty()) return null; |
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|
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|
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BoundablePair bp = new BoundablePair(this.getRoot(), this.getRoot(), itemDist); |
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return nearestNeighbour(bp); |
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} |
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|
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/** |
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* Finds the item in this tree which is nearest to the given {@link Object}, |
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* using {@link ItemDistance} as the distance metric. |
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* A Branch-and-Bound tree traversal algorithm is used |
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* to provide an efficient search. |
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* <p> |
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* The query <tt>object</tt> does <b>not</b> have to be |
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* contained in the tree, but it does |
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* have to be compatible with the <tt>itemDist</tt> |
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* distance metric. |
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* |
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* @param env the envelope of the query item |
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* @param item the item to find the nearest neighbour of |
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* @param itemDist a distance metric applicable to the items in this tree and the query item |
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* @return the nearest item in this tree |
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* or <code>null</code> if the tree is empty |
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*/ |
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public Object nearestNeighbour(Envelope env, Object item, ItemDistance itemDist) |
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{ |
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Boundable bnd = new ItemBoundable(env, item); |
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BoundablePair bp = new BoundablePair(this.getRoot(), bnd, itemDist); |
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return nearestNeighbour(bp)[0]; |
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} |
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|
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/** |
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* Finds the two nearest items from this tree |
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* and another tree, |
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* using {@link ItemDistance} as the distance metric. |
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* A Branch-and-Bound tree traversal algorithm is used |
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* to provide an efficient search. |
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* The result value is a pair of items, |
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* the first from this tree and the second |
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* from the argument tree. |
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* |
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* @param tree another tree |
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* @param itemDist a distance metric applicable to the items in the trees |
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* @return the pair of the nearest items, one from each tree |
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* or <code>null</code> if no pair of distinct items can be found |
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*/ |
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public Object[] nearestNeighbour(STRtree tree, ItemDistance itemDist) |
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{ |
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if (isEmpty() || tree.isEmpty()) return null; |
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BoundablePair bp = new BoundablePair(this.getRoot(), tree.getRoot(), itemDist); |
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return nearestNeighbour(bp); |
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} |
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|
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private Object[] nearestNeighbour(BoundablePair initBndPair) |
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{ |
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double distanceLowerBound = Double.POSITIVE_INFINITY; |
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BoundablePair minPair = null; |
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|
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|
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PriorityQueue priQ = new PriorityQueue(); |
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priQ.add(initBndPair); |
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|
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while (! priQ.isEmpty() && distanceLowerBound > 0.0) { |
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|
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BoundablePair bndPair = (BoundablePair) priQ.poll(); |
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double pairDistance = bndPair.getDistance(); |
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|
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/** |
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* If the distance for the first pair in the queue |
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* is >= current minimum distance, other nodes |
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* in the queue must also have a greater distance. |
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* So the current minDistance must be the true minimum, |
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* and we are done. |
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*/ |
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if (pairDistance >= distanceLowerBound) |
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break; |
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|
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/** |
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* If the pair members are leaves |
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* then their distance is the exact lower bound. |
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* Update the distanceLowerBound to reflect this |
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* (which must be smaller, due to the test |
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* immediately prior to this). |
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*/ |
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if (bndPair.isLeaves()) { |
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|
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distanceLowerBound = pairDistance; |
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minPair = bndPair; |
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} |
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else { |
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/** |
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* Otherwise, expand one side of the pair, |
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* and insert the expanded pairs into the queue. |
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* The choice of which side to expand is determined heuristically. |
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*/ |
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bndPair.expandToQueue(priQ, distanceLowerBound); |
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} |
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} |
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if (minPair == null) |
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return null; |
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|
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return new Object[] { |
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((ItemBoundable) minPair.getBoundable(0)).getItem(), |
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((ItemBoundable) minPair.getBoundable(1)).getItem() |
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}; |
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} |
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|
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/** |
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* Tests whether some two items from this tree and another tree |
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* lie within a given distance. |
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* {@link ItemDistance} is used as the distance metric. |
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* A Branch-and-Bound tree traversal algorithm is used |
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* to provide an efficient search. |
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* |
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* @param tree another tree |
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* @param itemDist a distance metric applicable to the items in the trees |
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* @param maxDistance the distance limit for the search |
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* @return true if there are items within the distance |
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*/ |
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public boolean isWithinDistance(STRtree tree, ItemDistance itemDist, double maxDistance) |
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{ |
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BoundablePair bp = new BoundablePair(this.getRoot(), tree.getRoot(), itemDist); |
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return isWithinDistance(bp, maxDistance); |
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} |
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|
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/** |
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* Performs a withinDistance search on the tree node pairs. |
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* This is a different search algorithm to nearest neighbour. |
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* It can utilize the {@link BoundablePair#maximumDistance()} between |
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* tree nodes to confirm if two internal nodes must |
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* have items closer than the maxDistance, |
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* and short-circuit the search. |
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* |
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* @param initBndPair the initial pair containing the tree root nodes |
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* @param maxDistance the maximum distance to search for |
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* @return true if two items lie within the given distance |
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*/ |
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private boolean isWithinDistance(BoundablePair initBndPair, double maxDistance) |
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{ |
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double distanceUpperBound = Double.POSITIVE_INFINITY; |
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|
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|
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PriorityQueue priQ = new PriorityQueue(); |
| 418 |
priQ.add(initBndPair); |
| 419 |
|
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while (! priQ.isEmpty()) { |
| 421 |
|
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BoundablePair bndPair = (BoundablePair) priQ.poll(); |
| 423 |
double pairDistance = bndPair.getDistance(); |
| 424 |
|
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/** |
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* If the distance for the first pair in the queue |
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* is > maxDistance, all other pairs |
| 428 |
* in the queue must have a greater distance as well. |
| 429 |
* So can conclude no items are within the distance |
| 430 |
* and terminate with result = false |
| 431 |
*/ |
| 432 |
if (pairDistance > maxDistance) |
| 433 |
return false; |
| 434 |
|
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/** |
| 436 |
* If the maximum distance between the nodes |
| 437 |
* is less than the maxDistance, |
| 438 |
* than all items in the nodes must be |
| 439 |
* closer than the max distance. |
| 440 |
* Then can terminate with result = true. |
| 441 |
* |
| 442 |
* NOTE: using Envelope MinMaxDistance |
| 443 |
* would provide a tighter bound, |
| 444 |
* but not much performance improvement has been observed |
| 445 |
*/ |
| 446 |
if (bndPair.maximumDistance() <= maxDistance) |
| 447 |
return true; |
| 448 |
/** |
| 449 |
* If the pair items are leaves |
| 450 |
* then their actual distance is an upper bound. |
| 451 |
* Update the distanceUpperBound to reflect this |
| 452 |
*/ |
| 453 |
if (bndPair.isLeaves()) { |
| 454 |
|
| 455 |
distanceUpperBound = pairDistance; |
| 456 |
|
| 457 |
/** |
| 458 |
* If the items are closer than maxDistance |
| 459 |
* can terminate with result = true. |
| 460 |
*/ |
| 461 |
if (distanceUpperBound <= maxDistance) |
| 462 |
return true; |
| 463 |
} |
| 464 |
else { |
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/** |
| 466 |
* Otherwise, expand one side of the pair, |
| 467 |
* and insert the expanded pairs into the queue. |
| 468 |
* The choice of which side to expand is determined heuristically. |
| 469 |
*/ |
| 470 |
bndPair.expandToQueue(priQ, distanceUpperBound); |
| 471 |
} |
| 472 |
} |
| 473 |
return false; |
| 474 |
} |
| 475 |
|
| 476 |
/** |
| 477 |
* Finds k items in this tree which are the top k nearest neighbors to the given {@code item}, |
| 478 |
* using {@code itemDist} as the distance metric. |
| 479 |
* A Branch-and-Bound tree traversal algorithm is used |
| 480 |
* to provide an efficient search. |
| 481 |
* This method implements the KNN algorithm described in the following paper: |
| 482 |
* <p> |
| 483 |
* Roussopoulos, Nick, Stephen Kelley, and Frédéric Vincent. "Nearest neighbor queries." |
| 484 |
* ACM sigmod record. Vol. 24. No. 2. ACM, 1995. |
| 485 |
* <p> |
| 486 |
* The query {@code item} does <b>not</b> have to be |
| 487 |
* contained in the tree, but it does |
| 488 |
* have to be compatible with the {@code itemDist} |
| 489 |
* distance metric. |
| 490 |
* |
| 491 |
* @param env the envelope of the query item |
| 492 |
* @param item the item to find the nearest neighbour of |
| 493 |
* @param itemDist a distance metric applicable to the items in this tree and the query item |
| 494 |
* @param k the K nearest items in kNearestNeighbour |
| 495 |
* @return the K nearest items in this tree |
| 496 |
*/ |
| 497 |
public Object[] nearestNeighbour(Envelope env, Object item, ItemDistance itemDist,int k) |
| 498 |
{ |
| 499 |
Boundable bnd = new ItemBoundable(env, item); |
| 500 |
BoundablePair bp = new BoundablePair(this.getRoot(), bnd, itemDist); |
| 501 |
return nearestNeighbourK(bp,k); |
| 502 |
} |
| 503 |
|
| 504 |
private Object[] nearestNeighbourK(BoundablePair initBndPair, int k) |
| 505 |
{ |
| 506 |
return nearestNeighbourK(initBndPair, Double.POSITIVE_INFINITY,k); |
| 507 |
} |
| 508 |
|
| 509 |
private Object[] nearestNeighbourK(BoundablePair initBndPair, double maxDistance, int k) |
| 510 |
{ |
| 511 |
double distanceLowerBound = maxDistance; |
| 512 |
|
| 513 |
|
| 514 |
PriorityQueue priQ = new PriorityQueue(); |
| 515 |
|
| 516 |
|
| 517 |
priQ.add(initBndPair); |
| 518 |
|
| 519 |
PriorityQueue kNearestNeighbors = new PriorityQueue(); |
| 520 |
|
| 521 |
while (! priQ.isEmpty() && distanceLowerBound >= 0.0) { |
| 522 |
|
| 523 |
BoundablePair bndPair = (BoundablePair) priQ.poll(); |
| 524 |
double pairDistance = bndPair.getDistance(); |
| 525 |
|
| 526 |
|
| 527 |
/** |
| 528 |
* If the distance for the first node in the queue |
| 529 |
* is >= the current maximum distance in the k queue , all other nodes |
| 530 |
* in the queue must also have a greater distance. |
| 531 |
* So the current minDistance must be the true minimum, |
| 532 |
* and we are done. |
| 533 |
*/ |
| 534 |
if (pairDistance >= distanceLowerBound){ |
| 535 |
break; |
| 536 |
} |
| 537 |
/** |
| 538 |
* If the pair members are leaves |
| 539 |
* then their distance is the exact lower bound. |
| 540 |
* Update the distanceLowerBound to reflect this |
| 541 |
* (which must be smaller, due to the test |
| 542 |
* immediately prior to this). |
| 543 |
*/ |
| 544 |
if (bndPair.isLeaves()) { |
| 545 |
|
| 546 |
|
| 547 |
if(kNearestNeighbors.size()<k){ |
| 548 |
kNearestNeighbors.add(bndPair); |
| 549 |
} |
| 550 |
else |
| 551 |
{ |
| 552 |
|
| 553 |
BoundablePair bp1 = (BoundablePair) kNearestNeighbors.peek(); |
| 554 |
if(bp1.getDistance() > pairDistance) { |
| 555 |
kNearestNeighbors.poll(); |
| 556 |
kNearestNeighbors.add(bndPair); |
| 557 |
} |
| 558 |
|
| 559 |
|
| 560 |
|
| 561 |
BoundablePair bp2 = (BoundablePair) kNearestNeighbors.peek(); |
| 562 |
distanceLowerBound = bp2.getDistance(); |
| 563 |
} |
| 564 |
} |
| 565 |
else { |
| 566 |
/** |
| 567 |
* Otherwise, expand one side of the pair, |
| 568 |
* (the choice of which side to expand is heuristically determined) |
| 569 |
* and insert the new expanded pairs into the queue |
| 570 |
*/ |
| 571 |
bndPair.expandToQueue(priQ, distanceLowerBound); |
| 572 |
} |
| 573 |
} |
| 574 |
|
| 575 |
|
| 576 |
return getItems(kNearestNeighbors); |
| 577 |
} |
| 578 |
private static Object[] getItems(PriorityQueue kNearestNeighbors) |
| 579 |
{ |
| 580 |
/** |
| 581 |
* Iterate the K Nearest Neighbour Queue and retrieve the item from each BoundablePair |
| 582 |
* in this queue |
| 583 |
*/ |
| 584 |
Object[] items = new Object[kNearestNeighbors.size()]; |
| 585 |
int count=0; |
| 586 |
while( ! kNearestNeighbors.isEmpty() ) |
| 587 |
{ |
| 588 |
BoundablePair bp = (BoundablePair) kNearestNeighbors.poll(); |
| 589 |
items[count]=((ItemBoundable)bp.getBoundable(0)).getItem(); |
| 590 |
count++; |
| 591 |
} |
| 592 |
return items; |
| 593 |
} |
| 594 |
} |
| 595 |
|
| 596 |
|